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49x^2+7x-318=0
a = 49; b = 7; c = -318;
Δ = b2-4ac
Δ = 72-4·49·(-318)
Δ = 62377
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{62377}=\sqrt{49*1273}=\sqrt{49}*\sqrt{1273}=7\sqrt{1273}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7\sqrt{1273}}{2*49}=\frac{-7-7\sqrt{1273}}{98} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7\sqrt{1273}}{2*49}=\frac{-7+7\sqrt{1273}}{98} $
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